Tricky infinite square root problem. How to solve never ending square root problem. Tricks to solve under roots upto infinity.

The

**square root**of a number is that number, the**of which is equal to the given number. There are**__square__**two types of square**root of a number Positive and Negative. Symbol showed above is the pictorial representation for "**Square Root**" also**Square Root**is represented by (number)^{(1/2)}.Example: 49 has two roots 7 and -7, because (7)

^{2}= 49 and (-7)

^{2}= 49. Hence, we can write (49)

^{1/2}= ±7.

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__Tricks (formula) for solving never ending square roots:__

__Tricks (formula) for solving never ending square roots:__

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** (i)** If the problem figure is of the type Fig.1 then, directly answer can be written as *x ***(****given number).**

**(**

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(ii) If the problem figure is of the type Fig.2 then, find the factors of *x*, such that thedifference between the factors is 1, then the larger factor will be result.

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__Some solved examples for infinite roots:__

#### 1) This example can be solved with the help of previously sited Square Root Formula(ii). Since 56 is the multiple of two consecutive numbers 7 and 8 and since 8>7. So, applying this Square root formula solution for above problem is 8.

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**2)** This example can be solved with the help of previously sited Square root Formula (i). Suppose the given expression is taken as *"x" *then *x*^{2} = 7x i.e., *x = 7,* thus directly we can apply the above identity to solve problems like of above.

^{2}= 7x i.e.,

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3) This is same as of the previous example. Only difference is in representation of numbers. If you look at the series 625, 25^{2} = 625, 5^{4} = 625.....all the numbers were same, only trick is applied on indexing the factors of 625. Thus directly solution for the above square root problem can be written as 625.

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**Calculating Square Root up-to infinity**let us know we will update our post and will**highlight your name**below the Post Body as editor. For any query drop your comment below and let us know our support team will get back to you as soon as possible.
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